Index was outside the bounds of the array.

[I_R_Lee]

How would I avoid that error? It happens on this line of code:

           txtWord.Text = Replace$(txtWord.Text.Chars(I), txtWord.Text.Chars(I), "*")

 

I've also tried

           txtWord.Text = Replace$(txtWord.Text, txtWord.Text.Chars(I), "*")

but I get the same error.

Any help?

[I_R_Lee]

Never mind, I just found the StringBuilder class, and that allows it!

[I_R_Lee]

Actually, I do need help.

I get that error on these lines instead:

       Dim SB As New System.Text.StringBuilder(CurWord)
       Dim SBW As New System.Text.StringBuilder(txtWord.Text)
       Dim SBG As New StringBuilder(txtGuess.Text)
       For I = 0 To SB.Length ' Here
           If SB(I) = SBG(I) Then ' Here
               txtWord.Text = Replace(SBW(I), SB(I), SBG(I), 1, I) ' and here
           End If
       Next

 

How do I stop that? Or at least, how do you replace individual characters?

[divil]

It should almost certainly be,

 

For I = 0 To SB.Length - 1

[I_R_Lee]

Thanks, that fixed the first line but the other two still give the same error.

[Derek Stone]

You're trying to access elements of a variable which isn't an array.

[I_R_Lee]

Is there a way to replace individual characters

e.g

Dim This As String = "ThisThis"
Dim That As String = "ThatThat"
txtWord.Text = This & That
For I = 0 To txtWord.Text - 1
txtWord.Text = Replace(txtWord.Text, This.Chars(I), That.Chars(I+1))
Next

Something like that, is it possible, if not, how would it be done with the string builder class?

[Derek Stone]

Coerce the string into a byte array using System.Text.Encoding.GetBytes().