8 / 5 = 1.6 (I want only the 1)

[zubie]

Hi All

 

In vb.net 8 mod 5 returns 3 (the remainder)

 

The calc I require is one that returns the 1

 

my code at the moment returns 2 on the above calc.

 

intBonus = cint(8/5)

 

Can anyone help here?

cheers

ZuBiE

[Jay1b]

Look at using truncate.

[AFterlife]

Hi All

 

In vb.net 8 mod 5 returns 3 (the remainder)

 

The calc I require is one that returns the 1

 

my code at the moment returns 2 on the above calc.

 

intBonus = cint(8/5)

 

Can anyone help here?

cheers

ZuBiE

I would use the built in Math.Floor() function to truncate. To go to the next highest it would be Math.Ceiling()

So something like intBonus=Math.Floor(intBonus)

Should do the trick.

[PlausiblyDamp]

try something like

intbonus = Convert.ToInt32(Math.Floor(8 / 5))

not tested though so use at your own risk ;)

[zubie]

I looked up truncate in the help (vb.net) and all I got was Int and Fix.

Both these round the number up and down

 

I only want to round down

[AFterlife]

I looked up truncate in the help (vb.net) and all I got was Int and Fix.

Both these round the number up and down

 

I only want to round down

That's what the Math.Floor() function does.

[zubie]

Excellent .. thats exactly what I was looking for ..

 

cheers

ZuBiE

[mskeel]

You could also do integer division in VB.net and have it work as it does in c++ -- truncating any decimal parts. This is EXTREMEly intuitive, so watch out...

 

use the backslash to divide. \.

 

So...

8 / 5 = 1.6

8 \ 5 = 1

[cyclonebri]

You could also do integer division in VB.net and have it work as it does in c++ -- truncating any decimal parts. This is EXTREMEly intuitive, so watch out...

 

use the backslash to divide. \.

 

So...

8 / 5 = 1.6

8 \ 5 = 1

 

 

That's cool..I didn't even know you could do that in VB.net