Evaluating Even Number of Characters

[tate]

I'm sure there has to be a simple way of doing this but I have spent hours pouring over web pages and books but can't get started in the right direction!

 

What I would like to do is evaluate a text box to determine if there is an even number of characters. I thought I could do use something like this;

 

IEEERemainder(txtField.Length, 2)

 

If the returned value was greater than 0 then apparently there would not be an even number of characters.

 

However the results were rather unpredictable.

 

Any suggestions would be greatly appreciated.

Tate

[NK2000]

do you mean by even that it is dividable by 2? (english is not my native language)

 

if yes then use this

 

if (txtField.Length % 2)

// code for even

else

// code for not even

 

 

if i understood you wrong, then please tell me :)

[tate]

I'm not aware of any such syntax. What does the "%" character do? I can't find any reference to it in the Visual Studio help index.

 

 

Thanks for the reply.

[PlausiblyDamp]

The code given is C# - % is the modulus operator (it returns the remainder after dividing two numbers)

 

if you are using vb then there is a mod function

 

If txtField.Length Mod 2 = 0 then
'even
else
'odd
end if

[NK2000]

oh this vb.... i just love c# (c-style) syntax :)

[tate]

Appears the Mod function returns the same thing as the IEEERemainder function.

 

Either will work fine now that I understand them better. Thanks for everyone's input.

 

 

Tate