Bitwise rotation???

Please have a look here,

http://www.xtremedotnettalk.com/t74824/s.html

- Sorry, don't know where to post this thread!?

Try something along the lines of

i = (i << 1) | (i >> 31);

/* This should work. I tried it in VB real quick, but not C#

Should be a lot quicker than the other version as well

Warning: may have problem with signed integers

I don't know how .NET treats them on bit shifts */

val = (val << 1) | (val >> 31);

I've found this...

#define ROTR(x,y,b) (((x)>>(y&((b)-1))) | ((x)<<((b)-(y&((b)-1)))))

it's for C++

could someone translate it to C# ?

x is value, y how many rotates and b how many bits the value has... Thx

isn't there a simplier way? I'm really confused!

I'm very new to C#, but what if you created a generic function like this:

   uint RolRight(uint x, byte y, byte b) // number, shift, bits
   {
     //#define ROTR(x,y,b) (((x)>>(y&((b)-1))) | ((x)<<((b)-(y&((b)-1)))))
     return (x >> (y & (b - 1))) | (x << (b - (y & (b - 1))));
   }

And called it like one of these:

byte Ret = (byte)RolRight(0x81, 1, 8);

ushort Ret = (ushort)RolRight(0x8001, 1, 16);

uint Ret = RolRight(0x80000001, 1, 32);